I have no idea how this works, but that's not the point here.

I really need help on this algebra problem a+bx>cx-d , solve for x.

basically you want to make the equation so that you have x>something or xcx-d try to get all the x's on one side subtract bx from both sides a>cx-bx-d add d to both sides a+d>cx-bx undistribute a+d>(x)(c-b) divide both sides by (c-b) tada so the solution is >x or x<