**A hospital needs to dilute a 50% boric acid solution to a 10% solution.**

If it needs 25 liters of the 10% solution, how much of the 50% solution and how much water should be used?

**Answer**

You need one equation of this problem to balance the amount of a boric acid.

The amount of boric acid in 50% solution is expressed as 0.50*x Next, the amount of water is taken from 25 liters and x (based on 50% solution), that is 25 - x.

However, there is NO amount of BORIC ACID in water, and that is 0.

For the output solution, the amount of boric acid will be 0.10*2.5 = 2.5 Then, the balance equation is 0.50*x + 0*(25 - x) = 2.5 Solving for x, 0.50*x + 0 = 2.5 x = 2.5/0.5 = 5 Therefore the amount of liters in 50% solution is 5*0.50 = 2.5 liters The amount of water is 25 - 5 = 20 liters

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##### Upload Date: 5/31/2017

This 36 words question was answered by John B. on StudySoup on 5/31/2017. The question contains content related to Math Since its upload, it has received 46 views.