Q&A > Math > PROVE :(secA+tanA)2 =(1+sinA)/(1/sinA)

PROVE :(secA+tanA)2 =(1+sinA)/(1/sinA)

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PROVE :(secA+tanA)2 =(1+sinA)/(1/sinA)

Answer

[tex]A=x\\\\(secx+tanx)^2=\frac{1+sinx}{1-sinx}\\\\L=\left(\frac{1}{cosx}+\frac{sinx}{cosx}
ight)^2=\left(\frac{1+sinx}{cosx}
ight)^2=\frac{(1+sinx)^2}{cos^2x}\\\\=\frac{(1+sinx)^2}{1-sin^2x}=\frac{(1+sinx)^2}{1^2-sin^2x}=\frac{(1+sinx)^2}{(1-sinx)(1+sinx)}=\frac{1+sinx}{1-sinx}=R[/tex] $if R= frac 1+sinx frac 1 sinx = 1+sinx sinx=sinx+sin 2x then Leq R$ $secx= frac 1 cosx tanx= frac sinx cosx sin 2x+cos 2x=1 to cos 2x=1-sin 2x a 2-b 2= a-b a+b$

Virtual Teaching Assistant: John B.

Question Level: Basic

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Upload Date: 5/31/2017

This 6 words question was answered by John B. on StudySoup on 5/31/2017. The question contains content related to Math Since its upload, it has received 130 views.

PROVE :(secA+tanA)2 =(1+sinA)/(1/sinA)