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**PROVE :(secA+tanA)2 =(1+sinA)/(1/sinA)**

PROVE :(secA+tanA)2 =(1+sinA)/(1/sinA)

**Answer**

[tex]A=x\\\\(secx+tanx)^2=\frac{1+sinx}{1-sinx}\\\\L=\left(\frac{1}{cosx}+\frac{sinx}{cosx}

ight)^2=\left(\frac{1+sinx}{cosx}

ight)^2=\frac{(1+sinx)^2}{cos^2x}\\\\=\frac{(1+sinx)^2}{1-sin^2x}=\frac{(1+sinx)^2}{1^2-sin^2x}=\frac{(1+sinx)^2}{(1-sinx)(1+sinx)}=\frac{1+sinx}{1-sinx}=R[/tex]

##### Virtual Teaching Assistant: John B.

##### Question Level: Basic

##### Karma: Free

##### Upload Date: 5/31/2017

This 6 words question was answered by John B. on StudySoup on 5/31/2017. The question contains content related to Math Since its upload, it has received 199 views.